RVP is a very popular multiplex in the Garden City of Bangalore. It has five screens – Screen N, Screen C, Screen W, Screen, Screen B, Screen E. Five different movies – TKR, SP, TGST, PC and EQ- were screened over five consecutive days on these screens. Each movie was shown on a different screen every day. Similarly, each screen showed a different movie every day. The following points are known
- In all screens except C, SP was screened before EQ
- TKR as third movie to be screened on screen B and it was screened after PC
- PC was screened on other two screens prior to W and was screened on N immediately after it was screened on W
Q1) Which movie was screened on the first day at screen C?
- TGST
- EQ
- PC
- Can’t be determined
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Sol:
Let’s capture the information already given in the set in a table with Screens on columns and Movies in rows. We will fill each unique row-column with sequence number based on information provided in the set.
Movies | N | C | W | B | E | Remarks |
TKR | 3 | |||||
SP | 5 | 1/2/4 | ||||
TGST | ||||||
PC | 4 | 3 | 1/2 | |||
EQ | 1 | 2/4/5 |
- In all screens except C, SP was screened before EQ
It means, the sequence will be SP…EQ except for screen C.
Since, SP must be screened on number 5 and EQ must be displayed on number 1 on one of the screens. Let’s take SP as an example.
If SP is screened on screen N/W/B/E at 5th then EQ should be on 6th which is not possible.
Similarly, if EQ is screened on N/W/B/E at 1st then there is no possible place of SP
Hence, we can conclude that it is Screen C only where we can adjust these two.
- TKR as third movie to be screened on screen B and it was screened after PC
Mark TKR as 3rd on screen B and give possible sequences to SP, PC, EQ
- PC was screened on other two screens prior to W and was screened on N immediately after it was screened on W
PC is on 3rd at Screen W and 4th at Screen N
Now, consider PC out of 1,5,4,3 the only sequence left at that position is 2. Then complete the table with rest of the values taking references from row TKR.
Movies | N | C | W | B | E | Remarks |
TKR | 4 | 3 | ||||
SP | 5 | 2/4 | ||||
TGST | 3 | |||||
PC | 4 | 2 | 3 | 1 | 5 | |
EQ | 1 | 4/5 |
Let’s try to assign position 4 to SP other than B. We can’t give it to N, C and E (because 5 is given to PC and by rule EQ should get 5)
Case 1
Movies | N | C | W | B | E | Remarks |
TKR | 4 | 3 | ||||
SP | 5 | 4 | 2 | 4 can’t be given to N and E | ||
TGST | 3 | |||||
PC | 4 | 2 | 3 | 1 | 5 | |
EQ | 1 | 5 | 4/5 | If SP is given 4 in WàEQ at 5 |
Movies | N | C | W | B | E | Remarks |
TKR | 4 | 3 | ||||
SP | 5 | 4 | 2 | 4 can’t be given to N and E | ||
TGST | 3 | 3 | This is wrong | |||
PC | 4 | 2 | 3 | 1 | 5 | |
EQ | 1 | 5 | 4 | If SP is given 4 in WàEQ at 5 |
Hence, our assumption was wrong.
Case 2
Start with assigning 4th position to SP in B and 5th to EQ in B
Then TGST automatically get 2 in B
Look for places where you can assign 3 to SP so that EQ will get 4 and solve rest of the places by checking rows and columns. The final table will look like this
Movies | N | C | W | B | E | Remarks |
TKR | 1 | 4 | 5 | 3 | 2 | |
SP | 2 | 5 | 1 | 4 | 3 | Give 4 to B and 5 to EQ on B |
TGST | 5 | 3 | 4 | 2 | 1 | TGST automatically gets 2 on B |
PC | 4 | 2 | 3 | 1 | 5 | |
EQ | 3 | 1 | 2 | 5 | 4 | If SP is given 3 EQ will only get 4 in this case which is possible only at E |
Hence answer is ‘2’ (EQ was screened) [/bg_collapse]