RVP is a very popular multiplex in the Garden City of Bangalore. It has five screens – Screen N, Screen C, Screen W, Screen, Screen B, Screen E. Five different movies – TKR, SP, TGST, PC and EQ- were screened over five consecutive days on these screens. Each movie was shown on a different screen every day. Similarly, each screen showed a different movie every day. The following points are known
In all screens except C, SP was screened before EQ
TKR as third movie to be screened on screen B and it was screened after PC
PC was screened on other two screens prior to W and was screened on N immediately after it was screened on W
Q1) Which movie was screened on the first day at screen C?
TGST
EQ
PC
Can’t be determined
Sol:
Let’s capture the information already given in the set in a table with Screens on columns and Movies in rows. We will fill each unique row-column with sequence number based on information provided in the set.
Movies
N
C
W
B
E
Remarks
TKR
3
SP
5
1/2/4
TGST
PC
4
3
1/2
EQ
1
2/4/5
In all screens except C, SP was screened before EQ
It means, the sequence will be SP…EQ except for screen C.
Since, SP must be screened on number 5 and EQ must be displayed on number 1 on one of the screens. Let’s take SP as an example.
If SP is screened on screen N/W/B/E at 5th then EQ should be on 6th which is not possible.
Similarly, if EQ is screened on N/W/B/E at 1st then there is no possible place of SP
Hence, we can conclude that it is Screen C only where we can adjust these two.
TKR as third movie to be screened on screen B and it was screened after PC
Mark TKR as 3rd on screen B and give possible sequences to SP, PC, EQ
PC was screened on other two screens prior to W and was screened on N immediately after it was screened on W
PC is on 3rd at Screen W and 4th at Screen N
Now, consider PC out of 1,5,4,3 the only sequence left at that position is 2. Then complete the table with rest of the values taking references from row TKR.
Movies
N
C
W
B
E
Remarks
TKR
4
3
SP
5
2/4
TGST
3
PC
4
2
3
1
5
EQ
1
4/5
Let’s try to assign position 4 to SP other than B. We can’t give it to N, C and E (because 5 is given to PC and by rule EQ should get 5)
Case 1
Movies
N
C
W
B
E
Remarks
TKR
4
3
SP
5
4
2
4 can’t be given to N and E
TGST
3
PC
4
2
3
1
5
EQ
1
5
4/5
If SP is given 4 in WàEQ at 5
Movies
N
C
W
B
E
Remarks
TKR
4
3
SP
5
4
2
4 can’t be given to N and E
TGST
3
3
This is wrong
PC
4
2
3
1
5
EQ
1
5
4
If SP is given 4 in WàEQ at 5
Hence, our assumption was wrong.
Case 2
Start with assigning 4th position to SP in B and 5th to EQ in B Then TGST automatically get 2 in B
Look for places where you can assign 3 to SP so that EQ will get 4 and solve rest of the places by checking rows and columns. The final table will look like this
Movies
N
C
W
B
E
Remarks
TKR
1
4
5
3
2
SP
2
5
1
4
3
Give 4 to B and 5 to EQ on B
TGST
5
3
4
2
1
TGST automatically gets 2 on B
PC
4
2
3
1
5
EQ
3
1
2
5
4
If SP is given 3 EQ will only get 4 in this case which is possible only at E
